出售, USD 195,000
4358 Timuquana Road Unit 101, Jacksonville FL 32210, 杰克逊维尔, 佛罗里达, 美国
楼盘类型 : 公寓
楼盘设计 : N/A
建筑面积 : 1,194 ft² / 111 m²
占地面积 : N/A
卧室 : 3
浴室 : 2
浴室(企缸) : 0
MLS#: N/A
楼盘简介
Experience delightful living in this 3-bed, 2-bath condo in Venetia. On the second floor, it's bathed in natural light, creating an inviting atmosphere. The updated kitchen is a stylish fusion of form and function, making it a chef's haven. Outside, the Venetia neighborhood's charm enhances daily life. Enjoy community perks like a refreshing pool and outdoor grills for al fresco dining. Whether you crave relaxation by the pool, a modern kitchen, or a charming locale, this condo seamlessly blends comfort and style. Welcome home to a thoroughly enjoyable living experience.
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处于美国,佛罗里达,杰克逊维尔的“4358 Timuquana Road Unit 101, Jacksonville FL 32210”是一处1,194ft²杰克逊维尔出售公寓,USD 195,0003。这个高端的杰克逊维尔公寓共包括3间卧室和2间浴室。你也可以寻找更多杰克逊维尔的豪宅、或是搜索杰克逊维尔的出售豪宅。