出售, USD 195,000
(只供參考)
4358 Timuquana Road Unit 101, Jacksonville FL 32210, 傑克遜維爾, 佛羅里達, 美國
樓盤類型 : 公寓
樓盤設計 : N/A
建築面積 : 1,194 ft² / 111 m²
佔地面積 : N/A
睡房 : 3
浴室 : 2
浴室(企缸) : 0
MLS#: N/A
樓盤簡介
Experience delightful living in this 3-bed, 2-bath condo in Venetia. On the second floor, it's bathed in natural light, creating an inviting atmosphere. The updated kitchen is a stylish fusion of form and function, making it a chef's haven. Outside, the Venetia neighborhood's charm enhances daily life. Enjoy community perks like a refreshing pool and outdoor grills for al fresco dining. Whether you crave relaxation by the pool, a modern kitchen, or a charming locale, this condo seamlessly blends comfort and style. Welcome home to a thoroughly enjoyable living experience.
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位於美國,佛羅里達,傑克遜維爾的“4358 Timuquana Road Unit 101, Jacksonville FL 32210”是一處1,194ft²傑克遜維爾出售公寓,USD 195,000。這個高端的傑克遜維爾公寓共包括3間臥室和2間浴室。你也可以尋找更多傑克遜維爾的豪宅、或是搜索傑克遜維爾的出售豪宅。